If it's not what You are looking for type in the equation solver your own equation and let us solve it.
D( z )
z^(1/3) = 0
z < 0
z = 0
z^(1/3) = 0
z^(1/3) = 0
1*z^(1/3) = 0 // : 1
z^(1/3) = 0
z = 0
z < 0
z = 0
z = 0
z in (0:+oo)
(z^(-1/4)*z^(3/2))/(z^(1/3)) = 0
1*z^(11/12) = 0 // : 1
z^(11/12) = 0
z = 0
z in { 0}
z belongs to the empty set
| Cosx(2sinx-1)=0 | | 3x-2=x-7 | | -11=-6x-5x | | ax^2-bx+b-a=0 | | 1/16m-9=8 | | 2*Pi*t+sin(2*Pi*t)=f(t) | | 2w-8+2w= | | (z^-1/4)(z^3/2)/(z^1/3) | | -4r-7=15 | | 12x+15-32x-12+40-24x=36+60x+18 | | 28-k=22 | | (6t+2)(9t-6)= | | ln(x-13)=ln(2x+9) | | 6x-3/4=-5/8 | | -3x-x=-12 | | 53+x=x | | (5/2-4/2)/0-(6/2-8/0= | | d=1/5cb | | 4x-7=4(x+2) | | -1+14x=12x+17whatisx | | 29+15=69 | | 9x^2-12x+4x=0 | | -20n+250=-6(4n+10) | | 6x=.75x^2 | | 13=-t+9 | | (-7/2)y-4=(6/5)y-(3/2) | | 3x+7x=5x+50 | | ln(X-3)=ln(2X+9) | | W^2-8w-2=0 | | 5x+4-2=-8 | | -w^3+2w^2+63w= | | s(s-9)=-15 |